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Hcf of 1250 9375 15625

WebMar 12, 2024 · We can use this to figure out the HCF of 1250,9375,15625. This is how to do it. Step 1: The first step is to use the division lemma with 9375 and 1250 because 9375 is … WebHCF of 12, 45 and 75 can be represented as HCF of (HCF of 12, 45) and 75. HCF(12, 45, 75) can be thus calculated by first finding HCF(12, 45) using long division and thereafter …

Find the largest number which divides 1251, 9377 and 15628 …

WebDec 21, 2024 · So the divisor at this stage is the H.C.F. So the H.C.F of 38220 and 196 is 196. (iii) Given integers are 867 and 255. Clearly 867 > 225. Applying Euclid's division lemma to 867 and 225, we get, 867 = (225) (3)+192 Since the remainder 192 ≠ 0. Apply the division lemma to the divisor 225 and remainder 192. We get, 225= (192) (1)+33 WebAug 23, 2024 · 1251 – 1 = 1250, 9377 − 2 = 9375 and 15628 − 3 = 15625 which is divisible by the required number. Now, required number = HCF (1250, 9375, 15625) By Euclid’s division algorithm, b = a × q + r, 0 ≤ r < a Here, b is any positive integer . Firstly put b = 15625 and a = 9375 ⇒ 15625 = 9375 × 1 + 6250 ⇒ 9375 = 6250 × 1 + 3125 ⇒ 6250 = … gan charger amazon https://melodymakersnb.com

Greatest Common Factor (GCF, HCF, GCD) Calculator

WebAnswer: As 1, 2, and 3 are the remainders when required largest number (HCF) divides 1251, 9377 and 15628 respectively. We have the numbers for HCF (1251 – 1), (9377 – 2) and (15628 – 3) i.e., 1250, 9375, 15625 For HCF of 1250, 9375, 15625 let a = 15625, b = 9375 By Euclid’s division algorithm, a = bq + r 15625 = 9375 × 1 + 6250 WebApr 24, 2024 · Hcf of 1250 9375 15625 using Euclid's lemma Advertisement jazzy74 is waiting for your help. Add your answer and earn points. Answer 5 people found it helpful shirikavi here is your answer mate hcf =625 Find Math textbook solutions? Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 WebJun 1, 2024 · Find the HCF of 1250 and 9375 9375 = 1250 x 7 + 625 1250 = 625 x 2 + 0 thus 625 is the HCF Now, find the HCF of 625 and 15625 15625 = 625 x 25 + 0 Thus … gan charger 60w

Highest Common Factor of 1250, 9375, 15625 using Euclid

Category:Using Euclid’s division algorithm, find the largest number

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Hcf of 1250 9375 15625

NCERT Exemplar Solutions for Class 10 Maths Chapter 1 Real …

WebNow, required number = HCF of 1250, 9375 and 15625 [for the largest number] By Euclid's division algorithm, a = bq + r [∵ Dividend=Divisor×Quotient+Remainder] For largest number, put a = 15625 and b = 9375 15625 = 9375×1+6250 9375 = 6250×1+3125 6250 = 3125×2+0 HCF (15625, 9375) = 3125 WebNov 25, 2024 · So, required number = HCF of 1250, 9375 and 15625. By Euclid’s division algorithm, 15625 = 9375 x 1 + 6250 9375 = 6250 x 1 + 3125 6250 = 3125 x 2 + 0 =&gt; …

Hcf of 1250 9375 15625

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WebApr 24, 2024 · Hcf of 1250 9375 15625 using Euclid's lemma Advertisement jazzy74 is waiting for your help. Add your answer and earn points. Answer 5 people found it helpful … WebSolution: The prime factorization of 40 is 2 x 5. The prime factorization of 60 is 2 x 3 x 5. Step 2: List out the highest number of common prime factors of 40 and 60 ie., Step 3: Now, on multiplying the common prime factors we will get the HCF of two numbers. Thus, the Highest Common Factor of 40 and 60 is 20.

WebSep 30, 2012 · Best Answer. Copy. Factor them. 2 x 3 x 5 x 5 x 7 = 1050. 5 x 5 x 7 x 7 = 1225. Select the common factors. 5 x 5 x 7 = 175, the GCF. Wiki User. WebThe greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF = 6. Greatest Common Factor of 0. Any non zero whole number times 0 equals 0 so it is true that every non zero whole …

WebThe GCF of 50 and 150 is 50. Steps to find GCF. Find the prime factorization of 50 50 = 2 × 5 × 5; Find the prime factorization of 150 150 = 2 × 3 × 5 × 5; To find the GCF, multiply … WebFeb 22, 2024 · 1251 – 1 = 1250, 9377 – 2 = 9375 and 15628 – 3 = 15625 has to be exactly divisible by the number. Thus, the required number should be the H.C.F of 1250, 9375 and 15625. First, consider 1250 and 9375 and apply Euclid’s division lemma . 9375 = 1250 x 7 + 625 . 1250 = 625 x 2 + 0 . ∴ H.C.F (1250, 9375) = 625

WebHCF of 1250, 9375 and 15625 is 625. So, the largest number which divides 1251, 9377 and 15628 leaving remainders 1, 2 and 3 respectively is 625 Problem 3 : Using Euclid's division algorithm find the HCF of 9828 and 14742. Solution : 14742 &gt; 9828 14742 = 9828x 1 + 4914 9828 = 4914x 2 + 0 HCF of (14742 and 9828) is 4914. Problem 4 :

WebMay 17, 2024 · HCF = 5 × 5 = 25. So, HCF of 25, 50 and 75 is 25. Advertisement Advertisement Aryanyo1003t Aryanyo1003t 25. and it's simple plzzz. Advertisement … gan charger power bankWebHCF (1250, 9375,15625) = 625. Therefore, 625 is the largest number which divides 1251, 9377 and 15628 leaving remainders, 1, 2 and 3, respectively. Try This: Using Euclid’s … gan charger insideWebDefinition : The greatest among the common divisor of two or more integers is the Greatest Common Divisor (G.C.D.) or Highest Common Factor (H.C.F.) of the given integers. (i) HC.F. of 32 and 54 Factors 32 = 1, 2, 4, 8, 16, 32 and factors of 54 = 1, 2, 3, 6, 9, 18, 27, 54 H.C.F. = 2 (ii) H.C.F. of 18 and 24 Factors of 18 = 1, 2, 3, 6, 9, 18 gan charger brandWebOn subtracting 1, 2, and 3 from 1251, 9377 and 15628 respectively, we get 1250, 9375 and 15625. Now we find the HCF of 1250 and 9375 using Euclid's division lemma 1250 < 9375 Thus, we divide 9375 by 1250 by using Euclid's division lemma 9375 = 1250 × 7 + 625 ∵ Remainder is not zero, ∴ we divide 1250 by 625 by using Euclid's division lemma black is the new black meaningWebHCF (1250,9375) = 625 now we divide 15625 by 625, we get quotient = 25 and remainder =0. since 1250, 9375 and 15625 are divisible by 625, it is the answer. YOU CAN ALSO CHECK THE ANSWER BY SUBSTITUTING THE VALUE IN QUESTION. IF YOU DIVIDE 1251,9377 AND 15628 BY 625, YOU WILL GET REMAINDERS 1,2 AND 3 … gan charger with displayWebAnswers (1) By Euclid’s division algorithm, 15625 = 9375 × 1 + 6250. 9375=6250 × 1+3125. 6250 = 3125 × 2 +0. Thus, HCF (15625, 9375,) = 3125. gan charge trappingWebHence, the HCF of the smallest prime number and the smallest composite number is 2. Solution 7 Any positive integer is of the form 6m, 6m + 1, 6m + 2, 6m + 3, 6m + 4, 6m + 5 … black is the colour song meaning