F x f x-π +sinx
WebIf F (x) is a differentiable function such that F (x)=f(x),∀x>0 and f(x2)=x2+x3, then f(4) equals. Q. Find the range of f(x)=sin−1(ln[x])+ln(sin−1[x]), where [x] is the greatest … WebIf we let μ = sin ( x) then d μ / d x = cos x → d μ = cos ( x) d x. That means that ∫ 0 π / 2 f ( sin ( x)) d x = ∫ 0 0 f ( μ) cos x d μ = 1 cos x ∫ 0 0 f ( μ) d μ and the left hand side can also be written as 1 cos x ∫ 0 0 f ( μ) d μ by substituting μ = sin ( x) . I am not sure if this correct.
F x f x-π +sinx
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WebIf ${\rm f}'\left(x\right) = \sin\left(x\right)$ and ${\rm f}\left(\pi\right) = 3$, then ${\rm f}\left(x\right) =\ ?$. I understand that the derivative of $-\cos\left(x\right)$ is $\sin\left(x\right)$, but i really don't understand where the $3$ comes from. I have tried everything that comes to mind but I am stuck on this question. WebThe Fourier series of an even function contains only cosine terms and is known as Fourier Series and is given by. f ( x) = a 0 2 + ∑ n = 1 ∞ a n c o s n x. a 0 = 1 π ∫ − π π f ( x) d x a n = 2 π ∫ 0 π f ( x) c o s n x d x. ∴ Let us first find. a 0 = 2 π ∫ …
Web(a) To find a polynomial that interpolates f at the given points, we need to find the coefficients a, b, c, and d such that p (x) = a + bx + cx^2 + dx^3 passes through the points (-π/6, sin (-π/6)), (0, sin (0)), (π/6, sin (π/6)), and (π/2, sin (π/2)). Using the interpolation formula for polynomials, we have: View the full answer Step 2/2 WebSolution The correct option is C satisfies Rolle's theorem but f ' π 4 = 0 Explanation for the correct option. Find the correct relation: Given, f ( x) = sin x e x f ( 0) = sin 0 e 0 = 0 and f ( π) = sinπ e π = 0 ⇒ f ( 0) = f ( π) = 0 Therefore, f ( x) is continuous in 0, π.
WebCompute the surface area of revolution of y=sinx about the x-axis over the interval [0,9π]. Question: Compute the surface area of revolution of y=sinx about the x-axis over the interval [0,9π]. WebIn sine and cosine terms, f ( x) = 1 π + 2 π ( cos ( 2 x) 1 − 2 2 + cos ( 4 x) 1 − 4 2 + cos ( 6 x) 1 − 6 2 + ⋯) But the answer in my book is given as f ( x) = 1 π + 1 2 sin ( x) + 2 π ( cos ( 2 x) 2 2 − 1 + cos ( 4 x) 4 2 − 1 + cos ( 6 x) 6 2 − 1 + ⋯) I don't understand how there is a sine term and the denominator of the cosines has − 1.
WebWhat is the value of d/dx [f−1 (x)] when x=2π, given that f (x)=2x−sinx and f−1 (2π)=π ? Show transcribed image text Expert Answer 100% (5 ratings) Transcribed image text: en x = 21, given that f (x) = 2x – sin x and What is the value f-1 (21) = 1 ? Select one O a. 1/3 O b. -1 o o Previous question Next question Get more help from Chegg
WebFeb 13, 2024 · h' (π/2) = (-sin (π/2)f (π/2) - cos (π/2)f' (π/2))/f 2 (x) = (-1f (π/2) - 0 (6))/f 2 (π/2) = -1/f (π/2) Need to find the value of f (π/2) f' (π/2) = 6 --> f' (x) = 6sin (x) might work f (x) = -6cos (x) + C f (π/3) = -6 (1/2) +C = -6 --> C = -3 f (x) = -6cos (x) -3 f (π/2) = -3 Therefore, h' (π/2) = -1/f (π/2) = 1/3 Upvote • 1 Downvote Comments • 5 flights washington dc to denverWebTour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site chesapeake ham radio clubWebRelative maxima at: 5.831 (Separate multiple answers by commas.) Relative minima at-5.83 (Separate multiple answers by commas.) d) Find the x-value(s) where f'(x) has a relative maximum or minimum f' has relative maxima at: 5.83 f' has relative minima at: 1.19 (Separate multiple answers by commas.) (Separate multiple answers by commas.) flights washington dc to fort myers flWebAug 28, 2015 · [sin(x1*) +sin(x2*) +sin(x3*) + sin(x4*)]( π 2) where the xi* are the sample points. Explanation: [a,b] = [0,2π] and n = 4 so Δx = b − a n = 2π 4 = π 2 The Riemann sum with n = 4 is: [f (x1*) + f (x2*) +f (x3*) +f (x4*)]Δx where the xi* are the sample points. So, for this question we get: [sin(x1*) +sin(x2*) +sin(x3*) + sin(x4*)]( π 2) chesapeake gymWebThe formula for a n is. a n = 1 π ∫ − π π f ( x) cos ( n x) d x. Since your f is even, so is f ( x) cos ( n x), so we can integrate over [ 0, π] and double the result: a n = 2 π ∫ 0 π f ( x) cos ( n x) d x. On the interval [ 0, π], we have x sin ( x) = x sin ( x) so we can shed the absolute values when computing the integral: a ... chesapeake handWebFact: Using the substitution u=π−x,u=π−x, one can show that∫π0xf (sinx)dx=π2∫π0f (sinx)dx.∫0πxf (sinx)dx=π2∫0πf (sinx)dx. Use the fact given above to evaluate This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer chesapeake ham radioWebMar 29, 2016 · Using Calculator: ⇒ sin( π 6) = .5 Explanation: Solution Strategy: Use the definition of Taylor series for a function, f (x) given by: f (x) = f (a) + f ′(a) x − a 1! +f (a) … chesapeake gynecology salisbury md